Molecular Geometry & Molecular Shape:

What is Molecular Geometry?

Molecular geometry is the three-dimensional shape or arrangement of atoms in a molecule. Molecular geometry involves the positioning of the atoms surrounding the central atom as well as the bond angles between them.

OR

Molecular geometry is how a molecule appears in three dimensions.

Importance of Molecular Geometry In Chemistry

  • Controls reactivity: Determines the reaction between molecules
  • Decides polarity: Determines if the molecule is polar or nonpolar
  • Influences properties: Determines boiling point, melting point, and solubility
  • Important in biology: Shape decides how enzymes and drugs work
  • Helps prediction: It is used to predict molecular behavior and stability

In short: Molecular geometry is important because it affects a molecule’s properties, reactions, and functions.

Molecular Shapes

When chemists talk about a molecule’s shape, they are referring to its geometry. Two molecules can share the same chemical formula yet behave completely differently because their atoms are arranged differently in 3D space.

The problem addressed by molecular geometry is, “What is the shape of a molecule?” And this shape determines most of its properties.

VSEPR Theory Fundamentals:

What is VSEPR?

The Valence Shell Electron Pair Repulsion (VSEPR) theory is a model employed in chemistry to determine the geometries of individual molecules through the determination of the number of valence electrons surrounding the central atom. The development of this model was mainly achieved by Ronald Gillespie and Ronald Nyholm in 1957. It built on earlier works by Nevil Sidgwick and Herbert Powell.

Core Principle:

Electron pairs in the valence shell of a central atom repel one another and arrange themselves to be as far apart as possible, thereby minimizing electrostatic repulsion and determining the molecule’s three-dimensional shape.

Electron pairs occupy space:

Both bonding pairs (shared between atoms) and lone pairs (non-bonding) occupy a region of space around the central atom and contribute to overall electron geometry.

Like Charges Repel:

All electron pairs are negatively charged, so they repel one another. The stable arrangement is the one that places pairs at maximum angular separation.

Lone Pairs Exert Greater Repulsion:

Lone pair electrons are attracted towards the nucleus more strongly and therefore lie in a larger solid angle than bonding electrons. The hierarchy of repulsions is: lone pair–lone pair > lone pair–bond pair > bond pair–bond pair.

Lone pair–lone pair > Lone pair–bonding pair > Bonding pair–bonding pair

Electron Pair Repulsion in Practice

Thinkabout water (H2O). Oxygen possesses four pairs ofelectrons in its outer shell – two pairs arebonded (to each hydrogen) and two areunshared. The perfect tetrahedral configurationpositions pairs 109.5° apart, but the two lone pairs reduce the H–O–H bond angle to around 104.5°. This compression, directly forecasted from the VSEPR repulsion hierarchy, correspondswith experimental data – a significantconfirmation of the theory outlined in Shriver & Atkins’ Inorganic Chemistry.

“The shape of a molecule is defined not just by the bonds, but by all electron pairs, includingboth bonding and non-bonding ones.”

 Main Molecular Geometries (No Lone Pairs)

If there are no lone pairs present on the central atom, then the electron geometry and molecular geometry are the same.

Linear – Bond Angle: 180°

Bonded atoms: 2 | Lone pairs on central atom: 0 | Example: CO₂, HCl, BeCl₂

The central atom is positioned midway between two bonding atoms along a straight axis. With just two regions of electrons present, maximum repulsion occurs when these regions point directly away from one another at angles of 180°.
Lesson in polarity for CO₂: Although carbon dioxide possesses two dipoles as a result of two polar C=O bonds, the perfect linearity results in both of these dipoles pointing in exactly opposite directions and canceling out each other. CO₂, therefore, is non-polar despite having polar bonds due to its symmetrical shap

linear bond angle examples

Trigonal Planar – Bond Angle: 120°

Bonded atoms: 3 | Lone pairs: 0 | Example: BF₃, SO₃, NO₃⁻
A trigonal planar molecular geometry model has one atom in the centre and three atoms at the corners of an equilateral triangle, known as peripheral atoms, all in the same plane. All three ligands in an ideal trigonal planar species are identical, and all bond angles are 120°. Molecules with three ligands which are non-identical deviate from this idealised geometry.

trigonal planar bond angle examples



Boron’s exception: BF₃ is trigonal planar, but boron in this molecule has only six electrons around it — it is a well-known exception to the octet rule. This is stable because the empty p orbital on boron can accept electron density. Always note this when discussing BF

Tetrahedral — Bond Angle: 109.5°

Bonded atoms: 4 | Lone pairs: 0 | Example: CH₄, CCl₄, SiF₄

It is impossible for four electron domains to exist in one plane because geometrical constraints make it necessary that they occupy three dimensions.The perfect tetrahedral arrangement at 109.5° gives maximum separation.

Why tetrahedral geometry dominates chemistry and biology: Carbon forms four bonds and adopts tetrahedral geometry in virtually every organic molecule. The three-dimensional structure of proteins, carbohydrates, fats, and DNA all trace back to the tetrahedral carbon center. Without tetrahedral carbon, the molecular complexity necessary for life would be impossible

tetrahedral bond angle examples

Trigonal Bipyramidal – Bond Angles: 120° (equatorial) and 90° (axial)

Bonded atoms: 5 | Lone pairs: 0 | Example: PCl₅, AsF₅

Three atoms reside in the triangular equatorial plane, which is separated by 120° between each other, while one more atom occupies both top and bottom (axial positions) at 90° relative to the atoms in the equatorial plane. Only in this type of geometry are not all bonding sites equal because the angles between atoms as well as the chemical environment are different for each position. Lone pair electrons that are present in the molecule prefer equatorial positions over axial.

trigonal bipyramidal examples

Octahedral — Bond Angle: 90°

Bonded atoms: 6 | Lone pairs: 0 | Example: SF₆, [Fe(CN)₆]³⁻

Six bonded atoms surround the central atom: four in a square plane, one directly above, one directly below. All bond angles are 90°. The shape resembles two square pyramids joined base-to-base.

Octahedral geometry is critical in transition metal coordination chemistry. Many industrial catalysts, biologically active metal centers, and colorful coordination complexes adopt octahedral arrangements.

octahedral  molecular geometry

 Molecular Geometries with Lone Pairs:

Once lone pairs appear on the central atom, molecular geometry changes.

Bent — One Lone Pair (AX₂E₁)

Molecular geometry: Trigonal planar | Molecular shape: Bent | Bond angle: <120° (~117–119°) | Example: SO₂, O₃

Three electron domains arrange themselves in a trigonal planar electron geometry. One of those three positions is a lone pair — not a bonded atom. From the perspective of atomic positions only, the shape is bent. The lone pair pushes the two bonded atoms closer together, compressing the angle below 120°.

one lone pair structure

Trigonal Pyramidal (AX₃E₁)

Molecular geometry: Tetrahedral | Molecular shape: Trigonal pyramidal | Bond angle: ~107° | Example: NH₃, PCl₃, NF₃

Three electrons will take up positions in a trigonal planar electron arrangement. Out of these three positions, one will be occupied by a lone pair, which means that it will not be attached to any atoms. In terms of atomic position alone, the molecular geometry would be bent.

Trigonal Pyramidal (AX₃E₁)

Molecular geometry: Tetrahedral | Molecular shape: Trigonal pyramidal | Bond angle: ~107° | Example: NH₃, PCl₃, NF₃

The central atom has four electron regions. Three are bonds and one is a lone pair. The three bonded atoms form a pyramid shape.

Ammonia (NH₃) is the best example. The lone pair pushes the hydrogen atoms slightly closer together, reducing the bond angle from 109.5° to about 107°.

Important:
Trigonal planar → no lone pair, flat shape
Trigonal pyramidal → one lone pair, 3D shape

Bent — Two Lone Pairs (AX₂E₂)

Molecular geometry: Tetrahedral | Molecular shape: Bent | Bond angle: ~104.5° | Example: H₂O, H₂S

The central atom has four electron regions. Two are bonds and two are lone pairs. The lone pairs strongly repel the bonded atoms, making the bond angle even smaller.

Water (H₂O) is the most common example. Its bent shape makes water a polar molecule, which helps explain hydrogen bonding and many unique properties of water

The lone pair trend across four-domain molecules — a pattern directly tested in examinations:

Molecule

Lone Pairs

Bond Angle

CH₄ (Tetrahedral)

0

109.5°

NH₃ (Trigonal pyramidal)

1

~107°

H₂O (Bent)

2

~104.5°


The AXE Method:

The AXE notation is a simple way to show how many atoms and lone pairs are attached to the central atom so you can predict the molecule’s shape.

A = the central atom

X = No. of bonded atoms attached to the central atom

E = No. of lone pairs on the central atom

Shape Of Molecules Chart – Complete AXE Reference Table

AXE

Electron Geometry

Molecular Shape

Bond Angle

Example

AX₂

Linear

Linear

180°

CO₂

AX₃

Trigonal planar

Trigonal planar

120°

BF₃

AX₂E

Trigonal planar

Bent

<120°

SO₂

AX₄

Tetrahedral

Tetrahedral

109.5°

CH₄

AX₃E

Tetrahedral

Trigonal pyramidal

~107°

NH₃

AX₂E₂

Tetrahedral

Bent

~104.5°

H₂O

AX₅

Trigonal bipyramidal

Trigonal bipyramidal

90°, 120°

PCl₅

AX₄E

Trigonal bipyramidal

Seesaw

~90°, ~120°

SF₄

AX₃E₂

Trigonal bipyramidal

T-shaped

~90°

ClF₃

AX₂E₃

Trigonal bipyramidal

Linear

180°

XeF₂

AX₆

Octahedral

Octahedral

90°

SF₆

AX₅E

Octahedral

Square pyramidal

~90°

BrF₅

AX₄E₂

Octahedral

Square planar

90°

XeF₄

How to Determine Molecular Geometry: Step-by-Step

This simple four-step method can help you find the shape of almost any molecule.

Step 1: Draw the Lewis Structure

The Lewis structure shows how atoms and electrons are arranged in a molecule.

How to draw it:

  1. Choose the central atom
  2. Count total valence electrons
  3. Connect atoms with single bonds
  4. Add remaining electrons as lone pairs on outer atoms
  5. If needed, form double or triple bonds so atoms can complete their octet
  6. Place any leftover electrons on the central atom

Step 2: Count Electron Domains

An electron domain is any area of electrons around the central atom.Count them like this:

  • Single bond = 1 domain
  • Double bond = 1 domain
  • Triple bond = 1 domain
  • Lone pair = 1 domain

The total number of domains determines the basic arrangement around the central atom.

Domains

Arrangement

Ideal Bond Angle

2

Linear

180°

3

Trigonal planar

120°

4

Tetrahedral

109.5°

5

Trigonal bipyramidal

90°, 120°

6

Octahedral

90°

Step 3: Determine the Molecular Shape

Now focus only on the bonded atoms. Ignore lone pairs when naming the molecular shape.

Lone pairs still affect the shape because they push bonded atoms closer together.

Examples:

  • CH₄ → tetrahedral
  • NH₃ → trigonal pyramidal
  • H₂O → bent

More lone pairs = smaller bond angles.

Step 4: Write the Final Answer

A complete answer usually includes:

  • Molecular shape
  • Bond angle
  • Electron arrangement (optional but helpful)

Always remember:

  • Electron arrangement includes all electron domains
  • Molecular shape includes only bonded atoms

Bond Angles – Simple Explanation:

Bond angles are the angles between bonds around the central atom.

Factors That Affect Bond Angles

1. Electron Repulsion

Electron domains repel each other and spread out as much as possible to maintain a suitable distance to become stable.

2. Lone Pairs

Lone pairs repel more strongly than bonding pairs, so they reduce bond angles.

Example:

  • CH₄ = 109.5°
  • NH₃ = ~107°
  • H₂O = ~104.5°

More lone pairs cause more compression.

3. Electronegativity

Highly electronegative atoms pull electrons toward themselves, which can slightly change bond angles.

Example:

  • NH₃ has a bond angle of about 107°
  • NF₃ has a smaller bond angle of about 102°

Common Bond Angles

Shape

Bond Angle

Example

Linear

180°

CO₂

Trigonal planar

120°

BF₃

Tetrahedral

109.5°

CH₄

Trigonal pyramidal

~107°

NH₃

Bent

~104.5°

H₂O

Octahedral

90°

SF₆


Worked Examples

These examples use the same four-step method to find molecular geometry and bond angles.

H2O Molecular Geometry

Step 1 – Draw the Lewis Structure

  • Oxygen is the central atom
  • Oxygen has 6 valence electrons
  • Each hydrogen has 1 valence electron
  • Total = 8 valence electrons

Oxygen forms two O–H bonds and keeps two lone pairs.

Step 2 — Count Electron Domains

  • 2 bonding pairs
  • 2 lone pairs

Total = 4 electron domains

Step 3 — Determine the Shape

4 electron domains give a tetrahedral arrangement.

Since there are 2 lone pairs:

  • AX₂E₂
  • Molecular shape = Bent

Step 4 — Determine Bond Angle

Two lone pairs compress the angle from 109.5° to about 104.5°.

Answer:

  • Shape: Bent
  • Bond angle: ~104.5°
h2o molecular geometry

H2S Molecular Geometry

Step 1 – Draw the Lewis Structure

  • Sulfur is the central atom
  • Sulfur has 6 valence electrons
  • Each hydrogen has 1 valence electron
  • Total = 8 valence electrons

Sulfur forms two S–H bonds and keeps two lone pairs.

Step 2 – Count Electron Domains

Around the central sulfur atom:

  • 2 bonding pairs
  • 2 lone pairs

Total = 4 electron domainsains

Step 3 — Determine the Shape

4 electron domains give a tetrahedral arrangement.

Since there are 2 lone pairs:

  • AX₂E₂
  • Molecular shape = Bent

Step 4 — Determine Bond Angle

The two lone pairs compress the bond angle from the ideal tetrahedral angle (109.5°).

In H₂S, the bond angle is much smaller because sulfur is larger and bonding is weaker than in water.

Bond angle ≈ 92°

h2s molecular geometry

Answer:

  • Shape: Bent
  • Bond angle: ~92°


Why bond angle in h2s is less than h2o?

TheThe bond angle of H₂O (~104.5°) is greater than that of H₂S (~92°) because oxygen is more electronegative and smaller in size than sulfur. In water, the bonding electron pairs are drawn closer to the oxygen atom, resulting in stronger repulsion between electron pairs and a wider bond angle. In contrast, sulfur is larger and less electronegative, so the electron pair repulsions in H₂S are weaker, leading to a smaller bond angle.

BF3 Molecular Geometry

Step 1 – Draw the Lewis Structure

  • Boron is the central atom
  • Boron forms 3 single bonds with fluorine
  • Boron has no lone pairs

Step 2 – Count Electron Domains

  • 3 bonding pairs
  • 0 lone pairs

Total = 3 electron domains

Step 3 – Determine the Shape

  • AX₃
  • Shape = Trigonal planar

Step 4 — Determine Bond Angle

No lone pairs means no compression.

Answer:

  • Shape: Trigonal planar
  • Bond angle: 120°
bf3 molecular geometry

BF₃ is a flat molecule because all atoms lie in the same plane.

NH3 Molecular Geometry

Step 1 – Draw the Lewis Structure

  • Nitrogen is the central atom
  • Nitrogen forms 3 N–H bonds
  • Nitrogen has 1 lone pair

Step 2 – Count Electron Domains

  • 3 bonding pairs
  • 1 lone pair

Total = 4 electron domains

Step 3 – Determine the Shape

  • AX₃E
  • Shape = Trigonal pyramidal

Step 4 – Determine Bond Angle

One lone pair reduces the angle from 109.5° to about 107°.

Answer:

  • Shape: Trigonal pyramidal
  • Bond angle: ~107°
nh3 molecular geometry

NH₃ looks like a pyramid with nitrogen at the top.

HCN Molecular Geometry

Step 1 – Draw the Lewis Structure

  • Carbon is the central atom
  • Hydrogen has 1 valence electron
  • Carbon has 4 valence electrons
  • Nitrogen has 5 valence electrons
  • Total = 10 valence electrons

Carbon forms:

  • One single bond with hydrogen (H–C)
  • One triple bond with nitrogen (C≡N)

Nitrogen keeps one lone pair.

Step 2 – Count Electron Domains

Around the central carbon atom:

  • 2 bonding regions
    • One H–C bond
    • One C≡N bond (counts as one domain)
  • 0 lone pairs

Total = 2 electron domains

Step 3 – Determine the Shape

  • 2 electron domains give a linear arrangement.
  • Since there are no lone pairs on carbon:
  • AX₂
  • Molecular shape = Linear

Step 4 – Determine Bond Angle

Linear molecules have a bond angle of 180°.

hcn molecular geometry

Answer:

  • Shape: Linear
  • Bond angle: 180°

CO2 Molecular Geometry

Step 1 – Draw the Lewis Structure

Carbon forms two double bonds with oxygen:

O=C=O

Carbon has no lone pairs.

Step 2 – Count Electron Domains

Each double bond counts as one domain.

  • 2 bonding domains
  • 0 lone pairs

Total = 2 electron domains

Step 3 – Determine the Shape

  • AX₂
  • Shape = Linear

Step 4 – Determine Bond Angle

No lone pairs means no compression.

Answer:

  • Shape: Linear
  • Bond angle: 180°
co2 molecular geometry

Although the C=O bonds are polar, CO₂ is non-polar because the molecule is perfectly symmetrical.

XeF4 Molecular Geometry

Step 1 – Draw the Lewis Structure

  • Xenon is the central atom
  • Xenon has 8 valence electrons
  • Each fluorine has 7 valence electrons
  • Total = 36 valence electrons

Xenon forms four single bonds with fluorine atoms and keeps two lone pairs.

Step 2 – Count Electron Domains

Around the central xenon atom:

  • 4 bonding pairs
  • 2 lone pairs

Total = 6 electron domainsains

Step 3 — Determine the Shape

6 electron domains give an octahedral arrangement.

Since there are 2 lone pairs:

  • AX₄E₂
  • Molecular shape = Square planar

Step 4 – Determine Bond Angle

Step 4 — Determine Bond Angle

The fluorine atoms are arranged in the same plane, giving bond angles of:

  • Xe–F adjacent bond angle = 90°

Xe–F opposite bond angle = 180°

xef4 molecular geometry

Answer:

  • Shape: Square planar
  • Bond angle: 90° and 180°

ClF3 Molecular Geometry

Step 1 – Draw the Lewis Structure

  • Chlorine is the central atom
  • Chlorine has 7 valence electrons
  • Each fluorine has 7 valence electrons
  • Total = 28 valence electrons

Chlorine forms three single bonds with fluorine atoms and keeps two lone pairs.

Step 2 – Count Electron Domains

Around the central chlorine atom:

  • 3 bonding pairs
  • 2 lone pairs

Total = 5 electron domainsainsains

Step 3 — Determine the Shape

5 electron domains give a trigonal bipyramidal arrangement.

Since there are 2 lone pairs:

  • AX₃E₂
  • Molecular shape = T-shaped

Step 4 — Determine Bond Angle

The lone pairs compress the bond angles slightly from the ideal 90° and 180°.

Bond angles are approximately:

Axial F – Cl – Equatorial F ≈ 90°
(slightly less than 90° because lone pairs compress the angle)°

Axial F – Cl – Axial F ≈ 180°
(slightly less due to lone pair repulsion)

clf3 molecular geometry

Answer:

  • Shape: T-shaped
  • Bond angle: approximately < 90° and < 180°

Molecular Geometry Chart:

Bonded (X)

Lone (E)

AXE

Electron Geometry

Molecular Shape

Bond Angle

Example

2

0

AX₂

Linear

Linear

180°

CO₂

3

0

AX₃

Trigonal planar

Trigonal planar

120°

BF₃

2

1

AX₂E

Trigonal planar

Bent

<120°

SO₂

4

0

AX₄

Tetrahedral

Tetrahedral

109.5°

CH₄

3

1

AX₃E

Tetrahedral

Trigonal pyramidal

~107°

NH₃

2

2

AX₂E₂

Tetrahedral

Bent

~104.5°

H₂O

5

0

AX₅

Trigonal bipyramidal

Trigonal bipyramidal

90°, 120°

PCl₅

4

1

AX₄E

Trigonal bipyramidal

Seesaw

~90°, ~120°

SF₄

3

2

AX₃E₂

Trigonal bipyramidal

T-shaped

~90°

ClF₃

2

3

AX₂E₃

Trigonal bipyramidal

Linear

180°

XeF₂

6

0

AX₆

Octahedral

Octahedral

90°

SF₆

5

1

AX₅E

Octahedral

Square pyramidal

~90°

BrF₅

4

2

AX₄E₂

Octahedral

Square planar

90°

XeF₄

FAQS About Molecular Geometry

Rule of Solubility of Sulfates:
Sulfates are generally soluble in water. There are certain exceptions.
Barium Sulphate (BaSO₄),
Lead Sulphate (PbSO₄),
Mercury (I) Sulphate (Hg₂SO₄)
are insoluble and precipitate white solids. Calcium sulphate (CaSO₄) and Strontium Sulphate (SrSO₄) are slightly soluble and therefore considered insoluble in all practical cases. Sodium, Potassium, Copper, Zinc, and Ammonium sulfates are soluble and completely dissolved in water.

Yes, all nitrates (NO₃⁻) are water soluble without any exception at all. In this way, nitrates can be considered among the easiest rules within the entire field of solubility chemistry. All the ionic compounds having the nitrate anion, no matter what kind of metal ions they contain, will be dissolved completely in the solution. It is worth noting that even such compounds as silver nitrate (AgNO₃), lead nitrate (Pb(NO₃)₂), and barium nitrate (Ba(NO₃)₂) are entirely water-soluble, although silver, lead, and barium salts are not soluble in water when they are combined with other anions.

There are no salts that are invariably insoluble because all salts have some exceptions to their solubility rules. However, the salts that are considered to be generally insoluble in aqueous solution are carbonates (CO₃²⁻), hydroxides (OH⁻), phosphates (PO₄³⁻), and sulfides (S²⁻) associated with transition metals and main group metals.

Salts like iron(III) hydroxide (Fe(OH)₃), barium sulfate (BaSO₄), silver chloride (AgCl), lead iodide (PbI₂), and calcium carbonate (CaCO₃) are some of the most common insoluble salts that chemists encounter. It should be noted that these salts would also dissolve in water when associated with the metal ions of Group 1 such as sodium and potassium or the ammonium ion (NH₄⁺).

Hydroxides generally are insoluble in water, except for those of Group 1 hydroxides (such as LiOH, NaOH, KOH, RbOH, CsOH) and Ba(OH)₂, which are completely soluble and basic in nature.
Hydroxides generally are insoluble in water, except for those of Group 1 hydroxides (such as LiOH, NaOH, KOH, RbOH, CsOH) and Ba(OH)₂, which are completely soluble and basic in nature. Sr(OH)₂ is slightly soluble.

All other hydroxides (transition metals and nontransition metals) are insoluble in nature. They produce colored precipitates that are used to identify cations: brown Fe(OH)₃, blue Cu(OH).

Hydroxides generally are insoluble in water, except for those of Group 1 hydroxides (such as LiOH, NaOH, KOH, RbOH, CsOH) and Ba(OH)₂, which are completely soluble and basic in nature.
Hydroxides generally are insoluble in water, except for those of Group 1 hydroxides (such as LiOH, NaOH, KOH, RbOH, CsOH) and Ba(OH)₂, which are completely soluble and basic in nature. Sr(OH)₂ is slightly soluble.

All other hydroxides (transition metals and nontransition metals) are insoluble in nature. They produce colored precipitates that are used to identify cations: brown Fe(OH)₃, blue Cu(OH).

How do you know if a precipitate will form?
Predicting the formation of precipitation in the combination of solutions involves the following four steps:
List down all the ions present in both the solutions. Combining solutions of NaCl and AgNO₃ will form ions of Na⁺, Cl⁻, Ag⁺, and NO₃⁻.
Exchange of cation and anion of these ions will give rise to the formation of two products – AgCl and NaNO₃.


According to solubility rules, AgCl is insoluble, whereas NaNO₃ is soluble, hence a white precipitate of AgCl will be formed.
Reaction quotient Q will give a precise value where precipitation occurs when Q > Ksp, while precipitation does not occur when Q < Ksp and equilibrium exists when Q = Ksp.
In brief, precipitation occurs either according to solubility rules or when Q is greater than Ksp.

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